What will happen to a 0.25 M solution of sucrose when tested for conductivity?

A 0.25 M solution of sucrose will not conduct electricity, and as a result, the bulb will not light up. This is because sucrose is a non-electrolyte, meaning that when it dissolves in water, it does not dissociate into ions. Conductivity in solutions is primarily due to the presence of free-moving charged particles, such as ions.

In the case of sucrose, it dissolves completely to form molecules, but since there are no ions present to carry an electrical current, the solution does not conduct electricity. Thus, when tested for conductivity, the bulb remains off, confirming that the sucrose solution does not allow for the flow of electric current.