What is the primary energy requirement to lift a 20 kg dumbbell 1 meter?

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Study for the UCF CHM1020 Concepts in Chemistry Exam. Access flashcards and multiple-choice questions with explanations. Prepare comprehensively for your final exam!

To determine the primary energy requirement to lift a 20 kg dumbbell 1 meter, we need to consider the work done against gravity. The concept of work in physics is defined as the force applied to an object times the distance over which that force is applied. When lifting an object vertically against the force of gravity, the work done is equal to the gravitational force on the object multiplied by the height the object is lifted.

The force due to gravity on the dumbbell can be calculated using the formula:

[ \text{Force} = \text{mass} \times \text{acceleration due to gravity} ]

In this case:

  • The mass of the dumbbell is 20 kg.
  • The acceleration due to gravity is approximately 9.8 m/s².

Thus, the gravitational force acting on the dumbbell is:

[ 20 , \text{kg} \times 9.8 , \text{m/s}^2 = 196 , \text{N} ]

Now, to calculate the work done (or energy required) to lift the dumbbell 1 meter, we apply the work formula:

[ \text{Work} = \text{Force} \times \