What is the percentage, by mass, of carbon (C) in coal when approximated by the formula C135H96O9NS?

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To find the percentage by mass of carbon in the coal represented by the formula C135H96O9NS, you first need to determine the molar mass of the entire compound and the molar mass of just the carbon present within that formula.

For the compound C135H96O9NS:

  1. Calculate the molar mass of each element:
  • Carbon (C): 12.01 g/mol × 135 = 1621.35 g/mol
  • Hydrogen (H): 1.008 g/mol × 96 = 96.768 g/mol
  • Oxygen (O): 16.00 g/mol × 9 = 144.00 g/mol
  • Nitrogen (N): 14.01 g/mol × 1 = 14.01 g/mol
  • Sulfur (S): 32.07 g/mol × 1 = 32.07 g/mol
  1. Now, sum these values to get the total molar mass of the compound:
  • Total molar mass = 1621.35 + 96.768 + 144.00 + 14.01 + 32.07 = 1908.14 g/mol

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