What is the mass percent of fluorine in Halon 1211 (CBrClF2)?

To determine the mass percent of fluorine in Halon 1211 (CBrClF2), you begin by calculating the molar mass of the entire compound and then focus on the contribution of fluorine (F) to that total.

The molecular formula CBrClF2 indicates that the compound contains one carbon (C), one bromine (Br), one chlorine (Cl), and two fluorine (F) atoms. You can find the molar masses from the periodic table:

• Carbon (C): approximately 12.01 g/mol
• Bromine (Br): approximately 79.90 g/mol
• Chlorine (Cl): approximately 35.45 g/mol
• Fluorine (F): approximately 19.00 g/mol

Now, calculate the total molar mass of Halon 1211:

1. Total mass of carbon: 1 x 12.01 g/mol = 12.01 g/mol
2. Total mass of bromine: 1 x 79.90 g/mol = 79.90 g/mol
3. Total mass of chlorine: 1 x 35.45 g/mol = 35.45 g/mol
4. Total mass of fluorine