What is the mass of 5.83 × 10^17 molecules of liquid propane (C3H8)?

To calculate the mass of 5.83 × 10^17 molecules of liquid propane (C3H8), it is essential to understand the relationship between the number of molecules, the mole concept, and molar mass.

First, we need to calculate how many moles of propane are in 5.83 × 10^17 molecules. Knowing that one mole of any substance contains Avogadro's number of molecules (approximately 6.022 × 10^23 molecules), we can find the number of moles:

[ \text{moles of C3H8} = \frac{5.83 \times 10^{17} \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} ]

Calculating this gives:

[ \text{moles of C3H8} \approx 9.67 \times 10^{-7} \text{ moles} ]

Next, we need the molar mass of propane (C3H8). The molar mass can be calculated by adding the atomic masses of all the atoms in a propane molecule:

• Carbon (C) has an atomic mass of about 12