What is the atomic percentage composition of aluminum in an aluminosilicate with the formula Al2SiO5?

To determine the atomic percentage composition of aluminum in the compound Al₂SiO₅, you first need to find the total number of atoms in one formula unit of the compound and then calculate the fraction of those that are aluminum.

In Al₂SiO₅, there are:

• 2 aluminum (Al) atoms
• 1 silicon (Si) atom
• 5 oxygen (O) atoms

Adding these together gives a total of 2 (from Al) + 1 (from Si) + 5 (from O) = 8 atoms in total.

To find the atomic percentage of aluminum, divide the number of aluminum atoms by the total number of atoms, and then multiply by 100 to convert it to a percentage:

[ \text{Atomic percentage of Al} = \left( \frac{\text{Number of Al atoms}}{\text{Total number of atoms}} \right) \times 100 ]

Calculating this gives:

[ \text{Atomic percentage of Al} = \left( \frac{2}{8} \right) \times 100 = 25% ]

While it seems there could have been a misunderstanding in determining the correct percentage composition,