If 65.00 grams of silver nitrate are used in 3.0 L of solution, what is the molarity?

To determine the molarity of the solution, you need to divide the number of moles of the solute (in this case, silver nitrate) by the volume of the solution in liters.

First, calculate the molar mass of silver nitrate (AgNO₃). The atomic masses are approximately:

• Silver (Ag): 107.87 g/mol
• Nitrogen (N): 14.01 g/mol
• Oxygen (O): 16.00 g/mol

The molar mass of silver nitrate is calculated as follows: [ \text{Molar Mass} = 107.87 , \text{g/mol} + 14.01 , \text{g/mol} + (3 \times 16.00 , \text{g/mol}) ] [ = 107.87 + 14.01 + 48.00 = 169.88 , \text{g/mol} ]

Next, use the mass of silver nitrate to calculate the number of moles: [ \text{Moles of AgNO₃} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \